# SC2056 – ShellCheck Wiki

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## You probably wanted `&&`

here

### Problematic code:

```
if (( $1 != 0 || $1 != 3 ))
then
echo "$1 is not 0 or 3"
fi
```

### Correct code:

```
if (( $1 != 0 && $1 != 3 ))
then
echo "$1 is not 0 or 3"
fi
```

### Rationale:

This is not a bash issue, but a simple, common logical mistake applicable to all languages.

`(( $1 != 0 || $1 != 3 ))`

is always true:

- If
`$1 = 0`

then `$1 != 3`

is true, so the statement is true.
- If
`$1 = 3`

then `$1 != 0`

is true, so the statement is true.
- If
`$1 = 42`

then `$1 != 0`

is true, so the statement is true.

`(( $1 != 0 && $1 != 3 ))`

is true only when `$1`

is not `0`

and not `3`

:

- If
`$1 = 0`

, then `$1 != 3`

is false, so the statement is false.
- If
`$1 = 3`

, then `$1 != 0`

is false, so the statement is false.
- If
`$1 = 42`

, then both `$1 != 0`

and `$1 != 3`

is true, so the statement is true.

This statement is identical to `! (( $1 == 0 || $1 == 3 ))`

, which also works correctly.

### Exceptions

None.

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